Question

The value of p(x) = (x-1)(x+1)for p (1)

Answer 1

Step-by-step explanation:

if p(x)=(x-1)(x+1)=(x^2)-1^2

then p(1)=1^2-1^2 =0

Answer 2

Answer:

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➡ p(x) = (x - 1) (x + 1)

➡ p(x) = x² - 1

• It is in the form of (a - b) (a + b) = a² - b²

➡ p(1) = (1)² - 1

➡ p(1) = 1 - 1

➡ p(1) = 0

Hence, it is solved...

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Step-by-step explanation:

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