The value of p(y)=y²-y+1 for p(0) is:
a) -1
b) 3
c) -2
d) 1
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Answers
Answered by
0
Step-by-step explanation:
- p(-1) = -1² -1 +1
- =. 1 -1+1
- = -1 +1
- = 0
Answered by
2
Step-by-step explanation:
option d is right
i hope you understand
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