Question

the value of p(y)=y²-y+1 from p(0)​

Answer 1

Answer:

Step-by-step explanation:

0²-0+1=1

Value of y =1

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Answer 2

Answer:

p(0)=0^2-0+1=1

p(1)=1^2-1+1=1

p(2)=2^2-2+1=3