Physics, asked by rangini2020, 1 month ago

The value of permittivity of free space is ______ c^2n^-1m^-2​

Answers

Answered by anujmeena2306
1

Explanation:

Correct option is

C

8.854×10

−12

Nm

2

coulomb

2

From F=

4πε

o

1

r

2

q

2

If Force, F=1N

charge, q=1C

distance, r=1m

Then, q

o

=

F×4π×r

2

q

2

=

1N×4×3.14×(1m)

2

(1)

2

ε

o

=8.854×10

−12

Nm

2

C

2

Answered by Anonymous
3

Answer:

l hope it will help u ☺️✌️☺️

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