Question

The value of Planck's Constant is 6.67 into 10 ^ - 34Js. The velocity of light is 3.0 into 10^8 m/s. Which value is closest to the wavelength in nanometres of a quantum of light with frequency of 8*10^15 /s

Answer 1

Answer:

I hope this answer will help you

Answer 2

Answer:

The wavelength is 37.5 nm.

Explanation:

Given that,

Planck's constant $h= 6.67\times10^{-34}\ Js$

Speed of light $c= 3\times10^{8}\ m/s$

Frequency $f = 8\times10^{15}\ /s$

We need to calculate the wavelength

The wavelength is equal to the speed of light divided by the frequency.

Using formula of wavelength

$\lambda=\dfrac{c}{f}$

Put the value into the formula

$\lambda=\dfrac{ 3\times10^{8}}{8\times10^{15}}$

$\lambda=37.5\times10^{-9}\ m$

$\lambda=37.5\ nm$

Hence, The wavelength is 37.5 nm.