Question

the value of polynomial f(x)= x^2/9 + x/3 + 1 at x = 3​

Answer 1

Answer:

x=3

f(3)=(3)^2/9+3/3+1

f(3)=9/9+1+1

f(3)=1+1+1=3

Answer 2

Answer:

$\boxed{\underline{\Huge{\texttt{3}}}}$

Step-by-step explanation:

$\text{Here,}\\\\f(x)=\dfrac{x^2}{9} + \dfrac{x}{3} + 1=0\\\\g(x)=x-3=0\\\implies x=3\\\\\text{First we will simplify f(x),}\\\text{So,}\\\\\dfrac{x^2}{9} + \dfrac{x}{3} + 1=0\\\\\implies \dfrac{x^2}{9} + \dfrac{3x}{9} + \dfrac{9}{9}=0\\\\\implies \dfrac{x^2+3x+9}{9}=0\\\\\implies x^2+3x+9=0\times9\\\text{Now let's put the value of x in the above equation;}\\x^2+3x+9=0\times9\\\implies 3^2+3\cdot(3)+9=0\times9\\\implies 9+9+9 =0\times9\\\text{Now, let's bring back 9 to the L.H.S.;}$$\implies \dfrac{9+9+9}{9} = \dfrac{\cancel{27}}{\cancel{9}} = \dfrac{3}{1}=\bold{3}$