Question

the value of polynomial in x is x²+Kx+5 where k is a constant if x=2 value is 15 calculate the value when x=5​

Answer 1

Step-by-step explanation:

here it is

see it in the pic

Answer 2

Given:

The value of the polynomial in x is x²+Kx+5 where K is a constant. The value of the polynomial at x = 2 is 15.

To Find:

The value of the polynomial at x = 5 is?

Solution:

1. The given polynomial in x is x²+ Kx+ 5.

2. The value of the polynomial at x = 2 is 15. Substitute the value of x as 2,

=> x² + Kx + 5 at x = 2,

=> (2)² + K(2) + 5 = 15,

=> 4 + 2K + 5 = 15,

=> 2K = 15 - 9,

=> 2K = 6,

=> K = 6/2,

=> K = 3.

3. The polynomial is x²+ 3x + 5,

=> The value of the polynomial at x = 5 is,

=> (5)²+ 3(5) + 5,

=> 25 + 15 + 5,

=> 45.

Therefore, the value of the polynomial at x = 5 is 40.