Question

The value of polynomial x^2-x-1 at x= -1 is equal to *

Answer 1

Answer:

Since the polynomial \(f(x)=x^3+4x^2-px+8\) is exactly divisible by \((x-2)\) ,therefore 2 is a zero of polynomial \(f(x)\)

\(\Rightarrow f(2)=0\)

\(\Rightarrow 2^3+4\times 2^2-p\times 2+8=0\)

\(\Rightarrow 8+16-2p+8=0\)

\(\Rightarrow 2p=32\)

\(\Rightarrow \boldsymbol{p=16}\)

Step-by-step explanation:

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