Math, asked by komalkaur13222, 5 months ago

the value of product (y+1/y) and 1+10/y+16/y​

Answers

Answered by shashiawasthi069
3

Step-by-step explanation:

product (y+1/y) and 1+10/y+16/y

[ (y+1/y) ] ×[1+10/y+16/y]

y[1+10/y+16/y]+1/y[1+10/y+16/y]

y+y×10/y + y×16/y + 1/y + 10/y^2 + 16/y^2

y + 10 +16 +1/y + 26/y^2

26/y^2 + 1/y+ y +26

Answered by kingkarnal
0

Answer:

Step-by-step explanation:

product (y+1/y) and 1+10/y+16/y

[ (y+1/y) ] ×[1+10/y+16/y]

y[1+10/y+16/y]+1/y[1+10/y+16/y]

y+y×10/y + y×16/y + 1/y + 10/y^2 + 16/y^2

y + 10 +16 +1/y + 26/y^2

26/y^2 + 1/y+ y +26

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