Question

The value of px² - qy² at x = 1 and y = - 1 is

Answer 1

Given line is px

2

−qy

2

=0

General equation is ax

2

+by

2

+h=0

Comparing above equation with (i), we get

a=p,b=−q,h=0

Lines are real and distinct if h

2

−ab>0

⇒0+pq>0

⟹pq>0

Answer 2

Answer:

p*1 square- q-1 square

p1-q-1