The value of [qb+c] 64 [qc+aje-a [xa+b] ”
[2C+aje-a [2.a+b]a-b( where 2 + 0) i
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Step-by-step explanation:
a / (x - a) + b / (x - b) = 2c / (x - c)
=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)
=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + ab]
=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc
=> (a + b - 2c) x^2 = (2ab + ac + bc - 2ca -
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Answer:
Step-by-step explanation:
a / (x - a) + b / (x - b) = 2c / (x - c)
=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)
=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + ab]
=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc
=> (a + b - 2c) x^2 = (2ab + ac + bc - 2ca -
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