the value of quantum numbers n,l,ml for 5 electron of boron is.
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Hey Here's your answer
Given , no. of electron in boron is 5
Therefore n that is Principal quantum number , which denotes number of orbitals
Hence , n = 3 as the electronic configuration is 1s² 2s² 3p¹
.°. l = 0,1,2 ( as l = n-1 )
and , ml = -2,-1,0,1,2 ( as - l ≤ ml ≤+l)
Hope it helps ,
.....soddie
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