The value of radius of gyration for a uniform rod of mass M and length l is
a) 0.1 l
b)0.289 l
c) 0.389 l
d) 0.5
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Answer:
The moment of inertia of a rod of mass m about an axis perpendicular to it at one of its ends is given by I=ML
2
/3. Comparing this with the general equation for the moment of inertia, we get, I=MK
2
, K is the radius of gyration, we get K=L/√3
Hope this will help
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