Question

The value of (root 3-root 2) square

Answer 1

$Value \:of \: (\sqrt{3} - \sqrt{2})^{2} \\= (\sqrt{3})^{2} + (\sqrt{2})^{2} - 2 \times \sqrt{3}\times \sqrt{2}$

$\boxed { \pink { Since , (a-b)^{2} = a^{2} + b^{2} -2ab }}$

$= 3 + 2 - 2\sqrt{6} \\= 5 - 2\sqrt{6}$

Therefore.,

$\red{Value \:of \: (\sqrt{3} - \sqrt{2})^{2}}\green {= 5 - 2\sqrt{6}}$

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