Math, asked by ashwaniswami05, 3 months ago

The value of (Sec 0 + 1)(Sec 0-1)Coec²?0 is​

Answers

Answered by bannybannyavvari
0

Answer:

Besides that, we also know that the right angle is always equal to 90 degrees. sec y = 1cosec( y). sec 0 = 1cosec(0). sec 0 = 11. sec 0 = 1 ..

Answered by rkcomp31
2

Answer:

Step-by-step explanation:

\bf (\sec\theta+1)(\sec\theta-1)\ cosec^2\theta\\\\=(\sec^2\theta-1)\ cosec^2\theta\\\\=\frac{\tan^2 \theta}{\ sin^2\theta}\\\\=\frac{\sin^2\theta}{\cos^2\theta} \times \frac{1}{\sin^2\theta} \\\\=\frac{1}{\cos^2\theta}=\sec^2\theta

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