the value of sec^2x (1+ sinx)(1- sinx) is
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Step-by-step explanation:
sec ^2 x (1+sinx )(1‐sinx)
=sec^2x (1^2 - sin^2x)
=sec^2x (1‐ sin^2 x) ( 1‐sin^2x = cos ^2 x )
= sec^2x (cos ^2x)
= sec^2 x × 1/ sec^2 x
= 1
so,the answer is 1
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