Math, asked by vikirna03, 4 months ago

the value of sec^2x (1+ sinx)(1- sinx) is

Answers

Answered by yashopragnyasahoo
1

Step-by-step explanation:

sec ^2 x (1+sinx )(1‐sinx)

=sec^2x (1^2 - sin^2x)

=sec^2x (1‐ sin^2 x) ( 1‐sin^2x = cos ^2 x )

= sec^2x (cos ^2x)

= sec^2 x × 1/ sec^2 x

= 1

so,the answer is 1

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