Math, asked by thavitirajubaviri, 6 months ago

The value of sec (90-A)

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Answered by Anonymous

4

hope it helps you.........

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Answered by dilliprasaddhakal528

0

$\sec(90 -A) \\ \\ = \frac{1}{ \cos(90 - A) } \\ \\ = \frac{1}{ \sin A } \\ \\ = cosecA$

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