Question

the value of {(sec A+tan A)(1-sin A)} is equal to...


pls answer...will mark your answer as brainliest.​

Answer 1

Solution :

• we need to find the value of (sec A + tan A )(1 - sin A)

sec A can be written as 1/cos A and tan A can be written as sin A /cos A

›› (1/cos A + sin A /cos A)(1 - sin A)

›› [(1 + sin A)/ cos A)]( 1 - sin A)

we know that ( a + b)(a - b) = a² - b² So,

›› [(1 + sin A )(1 - sin A)]/cos A

›› (1² - sin² A)/cos A

›› (1 - sin² A)/cos A

• 1 - sin² A = cos² A

›› cos² A/cos A

›› cos A

More Formulas :

›› sin²A + cos²A = 1

›› Sin² A = 1 - cos² A

›› 1 + tan² A = sec²A

›› 1 + cot²A = cosec² A

›› Tan A = sin A/cos A

›› Cot A = cos A/sin A

›› Sec A = 1/cos A

›› Cosec A = 1/Sin A

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