The value of secθ × cosθ = ?
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cos theta =1/sec theta
so, sec theta ×1/sec theta
so the answer will be
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Theory :-
In an right angled triangle ABC, right angled at B
cosA = AB secA = AC
AC AB
sinA = BC coesecA = AC
AC BC
tanA = BC cotA = AB
AB BC
Solution :-
As we saw in the above theory
cosA × secA = AB × AC = 1
AC AB
Hence, for any θ
secθ × cosecθ = 1
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