Question

the value of sec square 35-tan square 35​

Answer 1

Answer:

2 (tan 35°/cot 55°) + (cot 55°/tan 35°)- 3 (sec 40°/cosec 50°)

= 2 {tan (90°-55°)/cot 55°} + {cot (90°-35°) /tan 35°} - 3 {sec (90°-50°)/cosec 50°}

= 2 (cot 55°/cot 55°) + (tan 35°/tan 35°) - 3 (cosec 50°/cosec 50°)

= 2 + 1 - 3

= 3 - 3

= 0 [REQUIRED ANSWER]