Question

The value of ( secθ+ tanθ) (1- sinθ) is equal to​

Answer 1

Now,

(secθ+tanθ)(1−sinθ)

=(  

cosθ

1

​  

+  

cosθ

sinθ

​  

)(1−sinθ)

=(  

cosθ

1+sinθ

​  

)(1−sinθ)

=  

cosθ

1−sin  

2

θ

​  

 

=  

cosθ

cos  

2

θ

​  

 [ Since 1−sin  

2

θ=cos  

2

θ]

=cosθ....

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