The value of ( secθ+ tanθ) (1- sinθ) is equal to
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Now,
(secθ+tanθ)(1−sinθ)
=(
cosθ
1
+
cosθ
sinθ
)(1−sinθ)
=(
cosθ
1+sinθ
)(1−sinθ)
=
cosθ
1−sin
2
θ
=
cosθ
cos
2
θ
[ Since 1−sin
2
θ=cos
2
θ]
=cosθ....
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