The value of sec theeta =√10 and theeta is an acute angle hence find the value of tan theeta - cot theeta
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Answered by
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Cosec theta = ✓10/1 = H/P
H = ✓10 , P = 1
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)²-(P)²
(B)² = (✓10)² - (1)²
(B)² = 10-1 => 9
B = ✓9 = 3
Therefore,
Sin theta = P/H = 1/✓10
Cos theta = B/H = 3/✓10
Tan theta = P/B = 1/3
Cot theta = B/P = 3/1
Sec theta = H/B = ✓10/3
Cosec theta = H/P = ✓10/1
Answered by
64
Cosec theta = ✓10/1 = H/P
H = ✓10 , P = 1
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)²-(P)²
(B)² = (✓10)² - (1)²
(B)² = 10-1 => 9
B = ✓9 = 3
Therefore,
Sin theta = P/H = 1/✓10
Cos theta = B/H = 3/✓10
Tan theta = P/B = 1/3
Cot theta = B/P = 3/1
Sec theta = H/B = ✓10/3
Cosec theta = H/P = ✓10/1
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