the value of sec0(1-sin0) (seco+tan0) is?
Answers
Answered by
3
Step-by-step explanation:
LHS=seco(1-sino)(seco+tano)
= 1/coso(1-sino)(1/coso + sino/coso)
= 1/coso (1-sino)(1+sino/coso)
= 1-sin^2o/cos^2o
= cos^2o/cos^2o
= 1
=RHS
Similar questions