Question

The value of sec²45º -tan²45º / sin²60º +cos²60º​

Answer 1

Answer:

1

Step-by-step explanation:

sec 45°=√2

sec^2 45°=2

tan 45°=1

tan^2 45°=1

sec ^2 45°-tan^2 45°= (2) -(1) =1

sin 60°=√3/2

sin^2 60°=3/4

cos 60°= 1/2

cos^2 60°=1/4

sin^2 60° + cos^2 60°= 3/4+1/4 = 1

sec^2 45°-tan^2 45° / sin^2 60°+ cos^2 60°= 1/1 = 1

OR

you can simply apply the formula of sec^2 x - tan^2 x = 1

and sin^2 x + cos ^2 x = 1 ........ you will get the same answer.

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