The value of sin 0 + sin(0 + 120°) - sin(120° - 0) = (2)
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0
Answer:
Correct option is
B
3
2π
sinxsin(120
0
−x)sin(120
0
+x)
=sinx[sin
2
120
0
−sin
2
x]
=sinx(
4
3
−sin
2
x)
=
4
1
sin3x
Fundamental period of sinax is
a
2π
So, period of
4
1
sin3x is
3
2π
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