Question

the value of sin 105 degree is

Answer 1

here is your correct answer

Answer 2

Answer:

$Value \: of \: sin105\degree=\frac{\sqrt{3}+1}{2\sqrt{2}}$

Step-by-step explanation:

$Value \: of \: sin105\degree\\=sin(60+45)$

$\boxed {sin(A+B)=sinAcosB+sinBcosA}$

$=sin60cos45+sin45cos60$

$=\frac{\sqrt{3}}{2}\times \frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\times \frac{1}{2}$

$=\frac{\sqrt{3}}{2\sqrt{2}}+\frac{1}{2\sqrt{2}}$

$=\frac{\sqrt{3}+1}{2\sqrt{2}}$

Therefore,

$Value \: of \: sin105\degree=\frac{\sqrt{3}+1}{2\sqrt{2}}$

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