Math, asked by krish699, 5 hours ago

The value of (sin^2+1÷1+tan^2)

those who will answer i will mark them as brainliest ​

Answers

Answered by anaghasethu1998
1

Step-by-step explanation:

(sin^2 + 1) / ( 1 + sin^2/cos^2)

(sin^2 + 1) / (( cos^2 + sin^2)/cos^2)

because sin^2 + cos^2 = 1

(sin^2 + 1) / (1/cos^2)

cos^2(sin^2 + 1)

Answered by ramkishorgoyal12
0

Answer:

sin²cos²+cos²

Step-by-step explanation:

(sin²+1 )/ 1+tan²

Solving the denominator

1+tan² = 1+ sin²/cos²

= (cos² + sin² )/cos ²

as cos² + sin²= 1

= 1/cos²

therefore, sin²+1/1+tan²

= (sin²+1)/ (1/cos²)

=(sin²+1)cos²

sin²cos² + cos²

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