Math, asked by harshith5610, 1 month ago

the value of sin^2 (30 degrees) + cos^2 (60 degrees)​

Answers

Answered by Anonymous
9

Answer:

 \sin {}^{2} 30 {}^{0}  +  \cos {}^{2}60 {}^{0}

 =(\frac{1}{2} ) {}^{2}  + ( \frac{1}{2} ) {}^{2}

 =  \frac{1}{4}  +  \frac{1}{4}

 =  \frac{1 + 1}{4}

  = \frac{2}{4}  =  \frac{1}{2}

Value =  \frac{1}{2}

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