Physics, asked by harshitasingh9431, 1 month ago

The value of sin^2a+sin^2B+sin^2y is

Answers

Answered by dhruvkalra168
1

Explanation:

You can derive by taking sin2A+sin2B and apply the formula, ie sin2A+sin2B = 2sin (2A+2B)/2. cos(2A-2B)/2, which is equal to 2sin (A+B). cos ( A-B)

And now thake sin2C and apply formula sin2c=2sinC. cosC

This gives,

2 sin (A+B). cos (A-B) + 2sinC. cosC

By solving the above mentioned sum you'll get the value, which is

4sinA. sinB. sinC

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