Math, asked by vedantkomkar153427, 2 months ago

The value of sinπ+2Cosπ+3sin3π/2 +4Cos3π/2-5secπ-6cosec3π/2=​

Answers

Answered by Anonymous
6

Question:

The value of

 sin \pi+2Cos \pi+3sin \frac{3 \pi} {2}+4Cos \frac{3 \pi} {2} -5sec \pi -6cosec \frac{3 \pi}{2}

Solution:

sin \pi+2Cos \pi+3sin \frac{3 \pi} {2}+4Cos \frac{3 \pi} {2} -5sec \pi -6cosec \frac{3 \pi}{2} \\ 0 + 2( - 1) + ( - 3cos0) + 4sin0 - 5( sec \pi) - 6( - sec0) \\ 0  - 2 - 3 + 0 + 5  + 6  \\ = 11 - 5 \\  = 6

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