Math, asked by SmileyDharshini, 10 months ago

the value of sin^2theta+1/1+tan^2theta​

Answers

Answered by dagiokgtesc
0

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Answered by Yazlin
2

(sin^2x+1)/(1+tan^2x)=

(sin^2x+1)/(1+[sin^2x/cos^2x])

( sin^2x+1)/([cos^2x+sin^2x]/cos^2x)

(sin^2x+1)cos^2x

(1+sin^2x)(1-sin^2x)=1-sin^4x

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