Question

The value of sin[3sin⁻¹(1/5)] is......,Select Proper option from the given options.
(a) - 3/5
(b) 79/12
(c) - 71/125
(d) 71/125

Answer 1

let sin^(-1){1/5} =A,

then

sinA=1/5,

therefore

sin[3A],

3sinA-4sin³A,

3×1/5 - 4×(1/5)³,

3/5 - 4/125,

(75-4)/125,

71/125✓✓✓✓