Question

the value of sin^6+ cos^6+3sin^2cos^2​

Answer 1

Answer:

1

Step-by-step explanation:

  $sin^{6}x+cos^{6}x+3sin^{2}x cos^{2}x$

= $sin^{6}x+cos^{6}x+3sin^{2}x cos^{2}x(sin^{2}x+cos^{2}x)$

= $(sin^{2}x+cos^{2}x)^{3}$

= 1.