Math, asked by nagaveni25508, 2 months ago



The value of sin 60° x cos 30º is :

Answers

Answered by ayushbehera70
5

Answer:

What is the value of sin (60+ theta)-cos (30-theta)?

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Suparna Paul

Answered 2 years ago

Let theta be equal to x.

sin ( 60°+x)

= sin 60.cos x + cos 60.sinx

=[(√3 cos x) /2 + (1 sin x) /2]

cos (30 - x)

= cos 30.cos x + sin 30.sin x

=[ (√3 cos x) /2 + (1 sin x) /2]

Therefore, sin ( 60 + x) - cos ( 30 - x)

= [(√3 cos x) /2 + (1 sin x) /2] - [(√3 cos x) /2 + (1 sin x) /2]

= 0

The answer is 0

Answered by lasya282
1
Let theta be equal to x.

sin ( 60°+x)

= sin 60.cos x + cos 60.sinx

=[(√3 cos x) /2 + (1 sin x) /2]

cos (30 - x)

= cos 30.cos x + sin 30.sin x

=[ (√3 cos x) /2 + (1 sin x) /2]

Therefore, sin ( 60 + x) - cos ( 30 - x)

= [(√3 cos x) /2 + (1 sin x) /2] - [(√3 cos x) /2 + (1 sin x) /2]

= 0

Hope it helps!
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