Question

The value of sin 7 1/2 degrees is

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given:

Consider the given trigonometric expression sin $7\frac{1}{2\\}$

Find:

The value of the expression

Solution:

Since we have

$cos2x=1-2sin^2x$

Let 2x = 15 degree

$cos15=1-2sin^2\frac{15}{2}$

$\frac{\sqrt{3}+1}{2\sqrt{2}} =1-2sin^2\frac{15}{2}$

$sin^2\frac{15}{2}=\frac{1}{2} (1-\frac{\sqrt{3}+1}{2\sqrt{2}})$

$sin^2\frac{15}{2}=\frac{2\sqrt{2}-\sqrt{3}-1}{4\sqrt{2}}$

$sin\frac{15}{2}=\sqrt{\frac{2\sqrt{2}-\sqrt{3}-1}{4\sqrt{2}}}$