The value of (sin 7x + sin 5x) /(cos 7x + cos 5x) + (sin 9x + sin 3x) / (cos 9x + cos 3x) is
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Answer:
LHS = [(sin7x + sin5x) + (sin9x + sin3x)] [(cos7x + cos5x) + (cos9x + cos3x)]
use the formula,
sinC + sinD = 2sin(C+D)/2.cos(C-D)/2 cosC + cosB = 2cos(C+D)/2.cos(C-D)/2
= {2sin6x.cosx +2sin6x.cos3x}/ {2cos6x.cosx + 2cos6x.cos3x}
- 2sin(x(cosx + cos3x)/ 2cos6x(cosx+cos3x)
= sin6x/cos6x
= tan6x = RHS
hence proved
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Answer:
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