Math, asked by varshaanand1615, 1 month ago

The value of (sin A-cosA)^(2)+ (sinA+cosA)^(2) is _________

Answers

Answered by niharika1834
0

Answer:

2

Step-by-step explanation:

(sinA−cosA)^2 + (sinA+cosA)^2

=sin^2A + cos^2A − 2sinAcosA + sin^2A + cos^2A + 2sinAcosA

=sin^2A + cos^2A + sin^2A + cos^2A

=1+1

=2

(since, sin^2A + cos^2A=1)

Answered by nkgaming1410
0

Step-by-step explanation:

(SinA-cosA)^2+(sinA+ cosA)^2

sin^2A+cos^2A-2(SinAcosA)+sin^2A+cos^2A+2(SinAcosA)

(a  -  b) ^{2}  = a ^{2}  + b ^{2}  - 2ab

(a + b)2=a2+b2 + 2ab

2sin^2A+2cos^2A

 sin^{2}   +  \cos  ^{2}  = 1

=2*1

=2

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