Math, asked by mrishi930, 10 months ago

The value of sin12 x cos18x sec78x cosec72 is __________________

Answers

Answered by singhalseema03p9uwqn

0

sin 12=cos78(standard complimentary formula)

cos18=sin72

eqn:

cos78*sin72*sec78*cosec72.

we know, sec 78=1/cos78

cosec72=1/sin72

(cos78*sin72)/(cos78*sin72)

=1 answer.

Answered by shobanamega7582

0

hiii mate

ur answer is

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