Math, asked by tanishdua14, 7 months ago

The value of (sin² 45° + 2tan² 45° — sec² 45°) is​

Answers

Answered by akashdjmgl
2

Step-by-step explanation:

answer sin 45 - 1/root 2

tan 45 - 1

sec 45 - root 2

(1/root 2 ) square + 2× (1) square - (root 2) square

1/2 + 2 - 2

1/ 2 +4/2 -4/2 = 1/2 answer

Answered by jaswasri2006
0

Values :-

  •  \sf sin \: 45 \degree =  \frac{1}{ \sqrt{2} }
  •  \sf tan \: 45 \degree = 1
  •  \sf sec  \:  45 \degree  =  \sqrt{2}

 \\  \\

 \sf ( { \frac{1}{ \sqrt{2} }) }^{2}  + 2 \times ( {1)}^{2}   -  ( { \sqrt{2)} }^{2}  =  \frac{1}{2}  +( 2 - 2) =  \frac{1}{2}

 \\

Mark as Brainliest answer please my friend

Similar questions