Question

The value of (sin² 45° + 2tan² 45° — sec² 45°) is​

Answer 1

Step-by-step explanation:

answer sin 45 - 1/root 2

tan 45 - 1

sec 45 - root 2

(1/root 2 ) square + 2× (1) square - (root 2) square

1/2 + 2 - 2

1/ 2 +4/2 -4/2 = 1/2 answer

Answer 2

Values :-

• $\sf sin \: 45 \degree = \frac{1}{ \sqrt{2} }$
• $\sf tan \: 45 \degree = 1$
• $\sf sec \: 45 \degree = \sqrt{2}$

$\sf ( { \frac{1}{ \sqrt{2} }) }^{2} + 2 \times ( {1)}^{2} - ( { \sqrt{2)} }^{2} = \frac{1}{2} +( 2 - 2) = \frac{1}{2}$

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