The value of sin² 5+ sin²10+sin²15________ +sin²85 + sin²90is equal to
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Tᴏ Fɪɴᴅ :-
value of sin² 5+ sin²10+sin²15________ +sin²85 + sin²90 ?
Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-
- sin(90 - A) = cosA
- sin²A + cos²A = 1 .
- sin45° = (1/√2)
- sin90° = 1
Sᴏʟᴜᴛɪᴏɴ :-
→ sin85 can be written as = sin(90 - 5) = cos5
Similarly,
→ sin80 = sin(90 - 10) = cos10
→ sin75 = sin(90 - 15) = cos15
_____________
_____________
_____________
→ sin50 = sin(90 - 40) = cos40° .
= Total Terms = 40/5 = 8 Terms.
___________
Now, After Putting These values Our Question becomes :-
➪ sin² 5+ sin²10+sin²15_________+cos²15 + cos²10 +cos²85 + sin²90
➪ (sin²5 + cos²5) + (sin²10 + cos²10) + (sin²15 + cos²15) ______________ + (sin²40 + cos²40) + sin²45 + sin²90
➪ 1 + 1 + 1 __________ 1 + (1/√2)² + (1)²
➪ 8 + (1/2) + 1
➪ 9 + (1/2)
➪ 9(1/2) (Ans.)
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