Question

the value of sin2 π/6+cos2 π/3-tan2 π/6​

Answer 1

Solution:-

${ \sin}^{2} ( \frac{\pi}{6} ) + { \cos }^{2} (\frac{\pi}{3} ) - { \tan }^{2} ( \frac{\pi}{6} )$

${ \sin }^{2} ( \frac{180}{6} ) + { \cos }^{2} ( \frac{180}{3} ) - { \tan}^{2} ( \frac{180}{6} )$

${ \sin}^{2} 30 + { \cos}^{2} 60 - { \tan }^{2} 30$

${( \frac{1}{2} )}^{2} + ( { \frac{1}{2} })^{2} - ({ \frac{ \sqrt{3} }{3} })^{2}$

$\frac{1}{4} + \frac{1}{4} - \frac{3}{9}$

$( \frac{1 + 1}{4} ) - \frac{3}{9}$

$\frac{1}{2}-\frac{3}{9}$

$\frac{9-3}{18}$

$\frac{1}{3}$

$\Large{\red{✓}}$

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Answer 2

Step-by-step explanation:

1/3 answer

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