The value of sin2x + sin5x- sin x/cos2x+ cos 5x+ cos x
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JO VALUE HOGA WAHI ANS. HOGA
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Step-by-step explanation:
sin2x + sin5x- sin x/cos2x+ cos 5x+ cos x
//We know that SinA - SinB = 2Cos(A+B/2)Sin(A-B/2)
CosA - CosB = 2Cos(A+B/2)Cos(A-B/2)
=> Sin2x + 2Cos(5x+x/2)Sin(5x-x/2) / Cos2x + 2Cos(5x+x/2)Cos(5x-x/2)
=> Sin2x + 2Cos3xSin2x / Cos2x + 2Cos3xCos2x
= Sin2x ( 1 + 2Cos3x) / Cos2x( 1 + 2Cos3x)
= Sin2x/Cos2x
= Tan2x
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