Question

The value of (Sin45°+Cos45°)
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

we know that.

$\sin45^{\circ} = \frac{1}{ \sqrt{2} } \\ \ \cos45^{\circ} = \frac{1}{ \sqrt{2} }$

$\sin45^{\circ} + \ \cos45^{\circ} \\ \Rightarrow \frac{1}{ \sqrt{2} } + \frac{1 }{ \sqrt{2} } \\ = > \frac{1 + 1}{ \sqrt{2} } \\ = > \frac{2}{ \sqrt{2} } = \frac{ \sqrt{2} \times \sqrt{2} }{ \sqrt{2} } = \sqrt{2} \\ = > \sqrt{2}$

Therefore, (Sin45°+Cos45°) = √2