The value of sin50∘−sin70∘+sin10∘ is
A) 1
B) 2
C) -1
D) 0
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Answered by
2
sin 50° -sin70°+sin10°=.766-.939+.173=0
RehanAhmadXLX:
bro.. u have to solve using identity
= 2 cos (120/2) sin(-20/2)
= 2 cos 60 sin (-10)
sin 50 - sin 70= -sin 10 ; (cos 60= 1/2 and sin(-A)= -sin A)
so,sin 50 - sin 70 + sin 10= -sin 10 + sin 10= 0
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