Math, asked by RehanAhmadXLX, 1 year ago

The value of sin50∘−sin70∘+sin10∘ is

A) 1

B) 2

C) -1

D) 0

Answers

Answered by navdeepsingh16091
2
sin 50° -sin70°+sin10°=.766-.939+.173=0

RehanAhmadXLX: bro.. u have to solve using identity
navdeepsingh16091: sin 50 - sin 70= 2 cos ((50+70)/2) sin ((50-70)/2)
                          = 2 cos (120/2) sin(-20/2) 
                          = 2 cos 60 sin (-10)
sin 50 - sin 70= -sin 10   ; (cos 60= 1/2 and  sin(-A)= -sin A)
so,sin 50 - sin 70 + sin 10= -sin 10 + sin 10= 0
navdeepsingh16091: used sinC-SinD=2cos(C+D)/2*sin(C-D)/2
itigupta123: cos(50+70)/2*sin(50-70)/2+sin10
itigupta123: sinA-sinB =2cos(A+B)/2*sin(A-B)/2
itigupta123: 2cos60*sin (-10)+sin10
itigupta123: 2*1/2 * (-sin10)+sin10
itigupta123: -sin10+sin10 = 0
itigupta123: That's why the answer is (D) : 0
Answered by Swarup1998
9
➡HERE IS YOUR ANSWER⬇

♧♧SOLUTION♧♧

sin50 - sin70 + sin10 \\  \\  = (2 \: cos \frac{50 + 70}{2}  \: sin \frac{50 - 70}{2} ) + sin10 \\  \\  = 2 \: cos60 \: sin( - 10) + sin10 \\  \\  =  - 2. \frac{1}{2} .sin10 + sin10 \\  \\  =  - sin10 + sin10 \\  \\  = 0

♧♧RULES♧♧

sin \alpha    -  sin \beta  \\  \\  = 2 \: cos \frac{ \alpha   +   \beta }{2}  \: sin \frac{ \alpha  -  \beta }{2}

sin( -  \alpha ) =  - sin \alpha

cos60 =  \frac{1}{2}

⬆HOPE THIS HELPS⬅
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