Question

The value of sine.cos (90° -0) + cos . sin (90° - 0) will be :​

Answer 1

cos (90°- ø) = sinø

sin (90°- ø) = cos ø

sinø.cos (90°- ø) + cos.sin (90°- ø)

=>sinø.sinø + cosø.cosø

=> sin²ø + cos²ø

=> 1

1 is the answer

Answer 2

Answer:

Answer will be 1

Step-by-step explanation:

sin0.cos(90-0)+cos0sin(90-0)

so

=sin0.sin0+cos0.cos0

:. [ cos(90-0)=sin0 and

sin(90-0)=cos0]

=sin^20+cos^20=1

I hope this will help you.

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