Question

the value of square root of (root12-root8)(root3+root2/5+root24
)

Answer 1

Answer:

Step-by-step explanation:

6+4  

12

​

−4  

24

​

−  

8

​

 

=6+2×  

3

​

×1+2×(−  

2

​

)×  

3

​

+2×1×(−  

2

​

)

=1+2+3+2×  

3

​

×1+2×(−  2 )×  3  +√2 × 1 × (−  2 )  = (1 + √ 3  − √ 2 )2

 

Hence square root of 6 + 4√12  − 4√24  −  8  is =±(1+  3 − 2 )