Question

The value of t for which the equation tx2 - 4x + 4 = 0 has equal roots is-
(1) 1
(2) 2
(3) 3
4​

Answer 1

Answer:

The answer is 1

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Step-by-step explanation:

ANSWER ::

For equal roots

Discriminant = 0

So

16 - 16t =0

t = 1

Answer 2

Answer:

The value of t for which the equation tx2 -4x + 4 = 0 has equal roots is 1.

Step-by-step explanation:

• The given equation is  tx2 - 4x + 4 = 0......................................(i)

• a$x^{2}$ + bx + c = 0 is a quadratic equation.

We know that , When a, b and c are real numbers, a ≠ 0 and discriminant D (i.e., b2 - 4ac = 0)  is zero , then the roots p and q of the quadratic equation ax2 + bx + c = 0 are real and equal.

Applying this in equation (i), we get

Discriminant D = $(-4)^{2}$ - 4.t.4 = 0

                          ⇒     16 - 16t = 0

                          ⇒         16 t  =  16

                          ⇒           t    =   1

So, the value of t for which the equation tx2 -4x + 4 = 0 has equal roots is 1.