Question

The value of (T1-T2) in the given diagram is

Answer 1

Answer:

$\frac{200}{3}(\sqrt{3}-1)$

Explanation:

find tension T3

10g - T = 10a

T - 55 = 5a  (adding both eqns)

T = T3 = $\frac{200}{3}$

at equilibrium

T2 cos 60 = T1 cos 30

on solving this we get

$\frac{T1}{T2}= \frac{1}{\sqrt{3} }$----(1)

using Laimi's theorem

T1 sin60 + T2 sin 30 = T3 sin 90

T1 $\sqrt{3}$/2 + T2/2 = T3

solving using eqn 1 $\frac{T1}{T2}= \frac{1}{\sqrt{3} }$

T1  = $200\frac{\sqrt{3} }{3}$

T2 = $\frac{200}{3}$

T1 - T2 = $200\frac{\sqrt{3} }{3}$ - $\frac{200}{3}$

           = $\frac{200}{3} (\sqrt{3} - 1 )$

best of luck mate !!