Question

The value of (tan 1 ^° tan 2^° ....... tan 88^° tan 89^° ) is _ .​

Answer 1

Answer:

YOUR ANSWER IS 1

Step-by-step explanation:

tan 1° tan 2° tan 3° … tan 89°

= [tan 1° tan 2° … tan 44°] tan 45°[tan (90° – 44°) tan (90° – 43°)… tan (90° – 1°)]

= [tan 1° tan 2° … tan 44°] [cot 44° cot 43°……. cot 1°]

= [tan 1°*cot 1°* tan 2°*cot 2°…..tan 44° * cot 44° ]

= We know that tanA *cotA=1

Hence, the equation becomes

= 1 x 1 x 1 x 1 x … x 1

= 1 { As 1ⁿ = 1}

Answer

tan 1° tan 2° tan 3° … tan 89° = 1

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Answer 2

Answer:

aur garden moves a lawn roller through a distance of 50 metre with a force of 50 newton incline at the angle of 60°to the direction of motion . calculate his wagesif he is paid to be 20 paise for doing work of 25j of work