The value of tan 1° tan 2° tan 3° ...... tan 89° is
(a)
(b) −1
(c)0
(d)None of these
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SOLUTION :
The correct option is (a) : 1
Given : tan 1° tan 2° tan 3° ………. tan 89°
tan 1° tan 2° tan 3° ………. tan 89°
= tan (90° - 89°) tan (90° - 88°) …….. tan 87° tan 88°tan 89°
= cot 89° cot 88°……... tan 87° tan 88°tan 89°
[tan θ = cot (90 - θ) ]
= (cot 89° tan 89° ) (cot 88° tan 88°)(cot 87° tan 87°
= 1 × 1 × 1
[tan θ × cot θ = 1]
tan 1° tan 2° tan 3° ………. tan 89° = 1
Hence, the value of tan 1° tan 2° tan 3° ………. tan 89° is 1.
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value of tan 1° tan 2° tan 3° ...... tan 89°
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